Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …010000111011000001101 |
3 | 11122020100020102122110221 |
4 | 103010002022013120031 |
5 | 132430340303400443 |
6 | 2441450052431341 |
7 | 163434023512342 |
oct | 23040212073015 |
9 | 4566306378427 |
10 | 1310001231373 |
11 | 4656285a836a |
12 | 191a78918551 |
13 | 966c0126223 |
14 | 4759394c7c9 |
15 | 24121e77eed |
hex | 1310228760d |
1310001231373 has 2 divisors, whose sum is σ = 1310001231374. Its totient is φ = 1310001231372.
The previous prime is 1310001231289. The next prime is 1310001231379. The reversal of 1310001231373 is 3731321000131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 675753049764 + 634248181609 = 822042^2 + 796397^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310001231373 is a prime.
It is a super-2 number, since 2×13100012313732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310001231379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655000615686 + 655000615687.
It is an arithmetic number, because the mean of its divisors is an integer number (655000615687).
Almost surely, 21310001231373 is an apocalyptic number.
It is an amenable number.
1310001231373 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310001231373 is an equidigital number, since it uses as much as digits as its factorization.
1310001231373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 1310001231373 in words is "one trillion, three hundred ten billion, one million, two hundred thirty-one thousand, three hundred seventy-three".
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