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13100020010404 = 223275005002601
BaseRepresentation
bin1011111010100001011000…
…0010100000110110100100
31201101100102220210111122021
42332220112002200312210
53204112320110313104
643510022140312524
72521305464561305
oct276502602406644
951340386714567
1013100020010404
1141a0761862a18
121576a56242744
13740432682c22
143340899b47ac
1517ab65525754
hexbea160a0da4

13100020010404 has 6 divisors (see below), whose sum is σ = 22925035018214. Its totient is φ = 6550010005200.

The previous prime is 13100020010309. The next prime is 13100020010419. The reversal of 13100020010404 is 40401002000131.

It can be written as a sum of positive squares in only one way, i.e., 6623005190400 + 6477014820004 = 2573520^2 + 2544998^2 .

It is a super-2 number, since 2×131000200104042 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1637502501297 + ... + 1637502501304.

Almost surely, 213100020010404 is an apocalyptic number.

It is an amenable number.

13100020010404 is a deficient number, since it is larger than the sum of its proper divisors (9825015007810).

13100020010404 is a wasteful number, since it uses less digits than its factorization.

13100020010404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3275005002605 (or 3275005002603 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13100020010404 its reverse (40401002000131), we get a palindrome (53501022010535).

The spelling of 13100020010404 in words is "thirteen trillion, one hundred billion, twenty million, ten thousand, four hundred four".

Divisors: 1 2 4 3275005002601 6550010005202 13100020010404