13100021143933 has 2 divisors, whose sum is σ = 13100021143934. Its totient is φ = 13100021143932.

The previous prime is 13100021143927. The next prime is 13100021144033. The reversal of 13100021143933 is 33934112000131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10326537261049 + 2773483882884 = 3213493^2 + 1665378^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100021143933 - 2³³ = 13091431209341 is a prime.

It is a super-3 number, since 3×13100021143933³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13100021143895 and 13100021143904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100021143903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550010571966 + 6550010571967.

It is an arithmetic number, because the mean of its divisors is an integer number (6550010571967).

Almost surely, 2^{13100021143933} is an apocalyptic number.

It is an amenable number.

13100021143933 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100021143933 is an equidigital number, since it uses as much as digits as its factorization.

13100021143933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 31.

The spelling of 13100021143933 in words is "thirteen trillion, one hundred billion, twenty-one million, one hundred forty-three thousand, nine hundred thirty-three".