Base | Representation |
---|---|
bin | 11101110010010011011101… |
… | …110000011110010111000000 |
3 | 122011211111110210001021202010 |
4 | 131302103131300132113000 |
5 | 114132301424042000000 |
6 | 1142340401024052520 |
7 | 36410311435010334 |
oct | 3562233560362700 |
9 | 564744423037663 |
10 | 131000223000000 |
11 | 38816978795342 |
12 | 12838879764140 |
13 | 5813363acba93 |
14 | 244c6320937c4 |
15 | 102293a6add50 |
hex | 7724ddc1e5c0 |
131000223000000 has 392 divisors, whose sum is σ = 433986901459056. Its totient is φ = 34874009600000.
The previous prime is 131000222999983. The next prime is 131000223000007. The reversal of 131000223000000 is 322000131.
It is a happy number.
It is a super-2 number, since 2×1310002230000002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a self number, because there is not a number n which added to its sum of digits gives 131000223000000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000223000007) by changing a digit.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 1778963182 + ... + 1779036818.
Almost surely, 2131000223000000 is an apocalyptic number.
131000223000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131000223000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (216993450729528).
131000223000000 is an abundant number, since it is smaller than the sum of its proper divisors (302986678459056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000223000000 is an frugal number, since it uses more digits than its factorization.
131000223000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74275 (or 74240 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 12.
Adding to 131000223000000 its reverse (322000131), we get a palindrome (131000545000131).
The spelling of 131000223000000 in words is "one hundred thirty-one trillion, two hundred twenty-three million", and thus it is an aban number.
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