Base | Representation |
---|---|
bin | 1011111010100001011010… |
… | …1010001001011000010110 |
3 | 1201101100110122100100111221 |
4 | 2332220112222021120112 |
5 | 3204112330240300042 |
6 | 43510023151120554 |
7 | 2521305652102606 |
oct | 276502652113026 |
9 | 51340418310457 |
10 | 13100030400022 |
11 | 41a0767709885 |
12 | 1576a5981315a |
13 | 74043487cc27 |
14 | 33408b11ac06 |
15 | 17ab663c8d67 |
hex | bea16a89616 |
13100030400022 has 4 divisors (see below), whose sum is σ = 19650045600036. Its totient is φ = 6550015200010.
The previous prime is 13100030400007. The next prime is 13100030400053. The reversal of 13100030400022 is 22000403000131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×131000304000222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100030399969 and 13100030400005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275007600004 + ... + 3275007600007.
It is an arithmetic number, because the mean of its divisors is an integer number (4912511400009).
Almost surely, 213100030400022 is an apocalyptic number.
13100030400022 is a deficient number, since it is larger than the sum of its proper divisors (6550015200014).
13100030400022 is an equidigital number, since it uses as much as digits as its factorization.
13100030400022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6550015200013.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 13100030400022 its reverse (22000403000131), we get a palindrome (35100433400153).
The spelling of 13100030400022 in words is "thirteen trillion, one hundred billion, thirty million, four hundred thousand, twenty-two".
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