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13100030414311 is a prime number
BaseRepresentation
bin1011111010100001011010…
…1010001100110111100111
31201101100110122101002010011
42332220112222030313213
53204112330241224221
643510023151311051
72521305652162351
oct276502652146747
951340418332104
1013100030414311
1141a0767719595
121576a5981b487
13740434886599
1433408b1220d1
1517ab663cd1e1
hexbea16a8cde7

13100030414311 has 2 divisors, whose sum is σ = 13100030414312. Its totient is φ = 13100030414310.

The previous prime is 13100030414293. The next prime is 13100030414323. The reversal of 13100030414311 is 11341403000131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100030414311 is a prime.

It is a super-2 number, since 2×131000304143112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100030414371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550015207155 + 6550015207156.

It is an arithmetic number, because the mean of its divisors is an integer number (6550015207156).

Almost surely, 213100030414311 is an apocalyptic number.

13100030414311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100030414311 is an equidigital number, since it uses as much as digits as its factorization.

13100030414311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13100030414311 its reverse (11341403000131), we get a palindrome (24441433414442).

The spelling of 13100030414311 in words is "thirteen trillion, one hundred billion, thirty million, four hundred fourteen thousand, three hundred eleven".