131000320213400 has 192 divisors, whose sum is σ = 336068433324000. Its totient is φ = 47092551680000.

The previous prime is 131000320213397. The next prime is 131000320213403. The reversal of 131000320213400 is 4312023000131.

It is an interprime number because it is at equal distance from previous prime (131000320213397) and next prime (131000320213403).

It is a super-2 number, since 2×131000320213400² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000320213403) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 144645176 + ... + 145548024.

Almost surely, 2^{131000320213400} is an apocalyptic number.

131000320213400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000320213400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168034216662000).

131000320213400 is an abundant number, since it is smaller than the sum of its proper divisors (205068113110600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000320213400 is a wasteful number, since it uses less digits than its factorization.

131000320213400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 903630 (or 903621 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131000320213400 its reverse (4312023000131), we get a palindrome (135312343213531).

The spelling of 131000320213400 in words is "one hundred thirty-one trillion, three hundred twenty million, two hundred thirteen thousand, four hundred".