131000321041440 has 384 divisors, whose sum is σ = 416637043200000. Its totient is φ = 34597860397056.

The previous prime is 131000321041433. The next prime is 131000321041483. The reversal of 131000321041440 is 44140123000131.

It is a super-2 number, since 2×131000321041440² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 131000321041440.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 37016195191 + ... + 37016198729.

It is an arithmetic number, because the mean of its divisors is an integer number (1084992300000).

Almost surely, 2^{131000321041440} is an apocalyptic number.

131000321041440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000321041440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (208318521600000).

131000321041440 is an abundant number, since it is smaller than the sum of its proper divisors (285636722158560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000321041440 is a wasteful number, since it uses less digits than its factorization.

131000321041440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5432 (or 5424 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131000321041440 its reverse (44140123000131), we get a palindrome (175140444041571).

The spelling of 131000321041440 in words is "one hundred thirty-one trillion, three hundred twenty-one million, forty-one thousand, four hundred forty".