Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …001101100111101110111 |
3 | 11122020100101011200211111 |
4 | 103010002101230331313 |
5 | 132430341311022333 |
6 | 2441450203215451 |
7 | 163434046435156 |
oct | 23040221547567 |
9 | 4566311150744 |
10 | 1310003220343 |
11 | 465629736744 |
12 | 191a79517587 |
13 | 966c067162c |
14 | 47593d0959d |
15 | 2412221c4cd |
hex | 1310246cf77 |
1310003220343 has 2 divisors, whose sum is σ = 1310003220344. Its totient is φ = 1310003220342.
The previous prime is 1310003220299. The next prime is 1310003220403. The reversal of 1310003220343 is 3430223000131.
It is a weak prime.
It is an emirp because it is prime and its reverse (3430223000131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310003220343 is a prime.
It is a super-2 number, since 2×13100032203432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310003220443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001610171 + 655001610172.
It is an arithmetic number, because the mean of its divisors is an integer number (655001610172).
Almost surely, 21310003220343 is an apocalyptic number.
1310003220343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310003220343 is an equidigital number, since it uses as much as digits as its factorization.
1310003220343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 1310003220343 its reverse (3430223000131), we get a palindrome (4740226220474).
The spelling of 1310003220343 in words is "one trillion, three hundred ten billion, three million, two hundred twenty thousand, three hundred forty-three".
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