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131000333120134 = 2293349164036109
BaseRepresentation
bin11101110010010011100100…
…010100100011001010000110
3122011211111202110020222011121
4131302103210110203022012
5114132302140234321014
61142340420000224154
736410314243012312
oct3562234424431206
9564744673228147
10131000333120134
1138816a24969215
12128388aa60b05a
135813380876a1a
14244c64295ab42
1510229451b2124
hex7724e4523286

131000333120134 has 16 divisors (see below), whose sum is σ = 197227632777840. Its totient is φ = 65257916940640.

The previous prime is 131000333120053. The next prime is 131000333120221. The reversal of 131000333120134 is 431021333000131.

It is a super-2 number, since 2×1310003331201342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000333120099 and 131000333120108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29972329 + ... + 34063780.

It is an arithmetic number, because the mean of its divisors is an integer number (12326727048615).

Almost surely, 2131000333120134 is an apocalyptic number.

131000333120134 is a deficient number, since it is larger than the sum of its proper divisors (66227299657706).

131000333120134 is a wasteful number, since it uses less digits than its factorization.

131000333120134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64039895.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 131000333120134 its reverse (431021333000131), we get a palindrome (562021666120265).

The spelling of 131000333120134 in words is "one hundred thirty-one trillion, three hundred thirty-three million, one hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 293 586 3491 6982 1022863 2045726 64036109 128072218 18762579937 37525159874 223550056519 447100113038 65500166560067 131000333120134