131000343144467 has 2 divisors, whose sum is σ = 131000343144468. Its totient is φ = 131000343144466.

The previous prime is 131000343144409. The next prime is 131000343144469. The reversal of 131000343144467 is 764441343000131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131000343144467 is a prime.

It is a super-2 number, since 2×131000343144467² (a number of 29 digits) contains 22 as substring.

Together with 131000343144469, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131000343144469) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500171572233 + 65500171572234.

It is an arithmetic number, because the mean of its divisors is an integer number (65500171572234).

Almost surely, 2^{131000343144467} is an apocalyptic number.

131000343144467 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000343144467 is an equidigital number, since it uses as much as digits as its factorization.

131000343144467 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 290304, while the sum is 41.

Adding to 131000343144467 its reverse (764441343000131), we get a palindrome (895441686144598).

The spelling of 131000343144467 in words is "one hundred thirty-one trillion, three hundred forty-three million, one hundred forty-four thousand, four hundred sixty-seven".