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13100034486199 is a prime number
BaseRepresentation
bin1011111010100001011011…
…1001101110111110110111
31201101100110221000221200211
42332220112321232332313
53204112332312024244
643510023414450251
72521306031611633
oct276502671567667
951340427027624
1013100034486199
1141a0769a4a891
121576a5b063987
13740435680a9b
1433408b8a1dc3
1517ab66934934
hexbea16e6efb7

13100034486199 has 2 divisors, whose sum is σ = 13100034486200. Its totient is φ = 13100034486198.

The previous prime is 13100034486191. The next prime is 13100034486269. The reversal of 13100034486199 is 99168443000131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13100034486199 - 23 = 13100034486191 is a prime.

It is a super-2 number, since 2×131000344861992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100034486191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550017243099 + 6550017243100.

It is an arithmetic number, because the mean of its divisors is an integer number (6550017243100).

Almost surely, 213100034486199 is an apocalyptic number.

13100034486199 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100034486199 is an equidigital number, since it uses as much as digits as its factorization.

13100034486199 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 49.

The spelling of 13100034486199 in words is "thirteen trillion, one hundred billion, thirty-four million, four hundred eighty-six thousand, one hundred ninety-nine".