Base | Representation |
---|---|
bin | 11101110010010011101000… |
… | …010100100101111100010000 |
3 | 122011211111221010120000212101 |
4 | 131302103220110211330100 |
5 | 114132302304430143100 |
6 | 1142340430355010144 |
7 | 36410316016353235 |
oct | 3562235024457420 |
9 | 564744833500771 |
10 | 131000400240400 |
11 | 38816a59842709 |
12 | 12838908b99954 |
13 | 5813391747862 |
14 | 244c64b82d78c |
15 | 102294b01e86a |
hex | 7724e8525f10 |
131000400240400 has 60 divisors (see below), whose sum is σ = 314738592246400. Its totient is φ = 52398473408640.
The previous prime is 131000400240377. The next prime is 131000400240401. The reversal of 131000400240400 is 4042004000131.
It is a super-2 number, since 2×1310004002404002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131000400240401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7208281 + ... + 17718919.
Almost surely, 2131000400240400 is an apocalyptic number.
131000400240400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000400240400 is an abundant number, since it is smaller than the sum of its proper divisors (183738192006000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000400240400 is a wasteful number, since it uses less digits than its factorization.
131000400240400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10541816 (or 10541805 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 131000400240400 its reverse (4042004000131), we get a palindrome (135042404240531).
The spelling of 131000400240400 in words is "one hundred thirty-one trillion, four hundred million, two hundred forty thousand, four hundred".
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