1310004112122 has 24 divisors (see below), whose sum is σ = 2838464673876. Its totient is φ = 436649201856.

The previous prime is 1310004112117. The next prime is 1310004112129. The reversal of 1310004112122 is 2212114000131.

1310004112122 is a `hidden beast` number, since 131 + 0 + 0 + 0 + 411 + 2 + 122 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 1295888533641 + 14115578481 = 1138371^2 + 118809^2 .

It is a super-2 number, since 2×1310004112122² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1310004112095 and 1310004112104.

It is not an unprimeable number, because it can be changed into a prime (1310004112129) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1137523 + ... + 1978374.

Almost surely, 2^{1310004112122} is an apocalyptic number.

1310004112122 is an abundant number, since it is smaller than the sum of its proper divisors (1528460561754).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310004112122 is a wasteful number, since it uses less digits than its factorization.

1310004112122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3139262 (or 3139259 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 1310004112122 its reverse (2212114000131), we get a palindrome (3522118112253).

The spelling of 1310004112122 in words is "one trillion, three hundred ten billion, four million, one hundred twelve thousand, one hundred twenty-two".