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131000437 is a prime number
BaseRepresentation
bin1111100111011…
…10100001110101
3100010111111211001
413303232201311
5232014003222
620555443301
73150325321
oct763564165
9303444731
10131000437
1167a45627
1237a56531
13211a8c69
1413580981
15b779e27
hex7cee875

131000437 has 2 divisors, whose sum is σ = 131000438. Its totient is φ = 131000436.

The previous prime is 131000423. The next prime is 131000491. The reversal of 131000437 is 734000131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126023076 + 4977361 = 11226^2 + 2231^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131000437 is a prime.

It is a super-2 number, since 2×1310004372 = 34322228988381938, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131030437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500218 + 65500219.

It is an arithmetic number, because the mean of its divisors is an integer number (65500219).

Almost surely, 2131000437 is an apocalyptic number.

It is an amenable number.

131000437 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000437 is an equidigital number, since it uses as much as digits as its factorization.

131000437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 19.

The square root of 131000437 is about 11445.5422326773. The cubic root of 131000437 is about 507.8758725493.

Adding to 131000437 its reverse (734000131), we get a palindrome (865000568).

The spelling of 131000437 in words is "one hundred thirty-one million, four hundred thirty-seven", and thus it is an aban number.