13100051213 has 2 divisors, whose sum is σ = 13100051214. Its totient is φ = 13100051212.

The previous prime is 13100051191. The next prime is 13100051273. The reversal of 13100051213 is 31215000131.

13100051213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11932940644 + 1167110569 = 109238^2 + 34163^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100051213 - 2⁶ = 13100051149 is a prime.

It is a super-2 number, since 2×13100051213² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13100051191 and 13100051200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100051273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550025606 + 6550025607.

It is an arithmetic number, because the mean of its divisors is an integer number (6550025607).

Almost surely, 2^13100051213 is an apocalyptic number.

It is an amenable number.

13100051213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100051213 is an equidigital number, since it uses as much as digits as its factorization.

13100051213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 13100051213 its reverse (31215000131), we get a palindrome (44315051344).

The spelling of 13100051213 in words is "thirteen billion, one hundred million, fifty-one thousand, two hundred thirteen".