Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1010001100101101011 |
3 | 110112010200112220000202 |
4 | 1322000101101211223 |
5 | 4121242230443034 |
6 | 140103034422415 |
7 | 12315220251065 |
oct | 1720021214553 |
9 | 415120486022 |
10 | 131001031019 |
11 | 506147375a1 |
12 | 2147bb91a0b |
13 | c4793b3091 |
14 | 64aa404735 |
15 | 361ab9a47e |
hex | 1e8045196b |
131001031019 has 2 divisors, whose sum is σ = 131001031020. Its totient is φ = 131001031018.
The previous prime is 131001030997. The next prime is 131001031039. The reversal of 131001031019 is 910130100131.
It is an a-pointer prime, because the next prime (131001031039) can be obtained adding 131001031019 to its sum of digits (20).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001031019 - 228 = 130732595563 is a prime.
It is a super-2 number, since 2×1310010310192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131001031039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500515509 + 65500515510.
It is an arithmetic number, because the mean of its divisors is an integer number (65500515510).
Almost surely, 2131001031019 is an apocalyptic number.
131001031019 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001031019 is an equidigital number, since it uses as much as digits as its factorization.
131001031019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 20.
The spelling of 131001031019 in words is "one hundred thirty-one billion, one million, thirty-one thousand, nineteen".
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