Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1010010010110010101 |
3 | 110112010200120001022002 |
4 | 1322000101102112111 |
5 | 4121242231043013 |
6 | 140103034445045 |
7 | 12315220263134 |
oct | 1720021222625 |
9 | 415120501262 |
10 | 131001034133 |
11 | 50614739972 |
12 | 2147bb93785 |
13 | c4793b4618 |
14 | 64aa40591b |
15 | 361ab9b358 |
hex | 1e80452595 |
131001034133 has 2 divisors, whose sum is σ = 131001034134. Its totient is φ = 131001034132.
The previous prime is 131001034121. The next prime is 131001034163. The reversal of 131001034133 is 331430100131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92499923044 + 38501111089 = 304138^2 + 196217^2 .
It is a cyclic number.
It is not a de Polignac number, because 131001034133 - 222 = 130996839829 is a prime.
It is a super-2 number, since 2×1310010341332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001034163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500517066 + 65500517067.
It is an arithmetic number, because the mean of its divisors is an integer number (65500517067).
Almost surely, 2131001034133 is an apocalyptic number.
It is an amenable number.
131001034133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001034133 is an equidigital number, since it uses as much as digits as its factorization.
131001034133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131001034133 its reverse (331430100131), we get a palindrome (462431134264).
The spelling of 131001034133 in words is "one hundred thirty-one billion, one million, thirty-four thousand, one hundred thirty-three".
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