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131001111242327 is a prime number
BaseRepresentation
bin11101110010010100010010…
…101100110110011001010111
3122011211120202200102200011002
4131302110102230312121113
5114132310233434223302
61142341025114133515
736410342441646164
oct3562242254663127
9564746680380132
10131001111242327
1138817294116a07
1212838a8712129b
135813475b39861
14244c6b802d06b
15102298d666c02
hex772512b36657

131001111242327 has 2 divisors, whose sum is σ = 131001111242328. Its totient is φ = 131001111242326.

The previous prime is 131001111242233. The next prime is 131001111242347. The reversal of 131001111242327 is 723242111100131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131001111242327 - 216 = 131001111176791 is a prime.

It is a super-2 number, since 2×1310011112423272 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131001111242327.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001111242347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500555621163 + 65500555621164.

It is an arithmetic number, because the mean of its divisors is an integer number (65500555621164).

Almost surely, 2131001111242327 is an apocalyptic number.

131001111242327 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001111242327 is an equidigital number, since it uses as much as digits as its factorization.

131001111242327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 131001111242327 its reverse (723242111100131), we get a palindrome (854243222342458).

The spelling of 131001111242327 in words is "one hundred thirty-one trillion, one billion, one hundred eleven million, two hundred forty-two thousand, three hundred twenty-seven".