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1310011997543 is a prime number
BaseRepresentation
bin10011000100000010110…
…011001011110101100111
311122020100222200121212222
4103010002303023311213
5132430401032410133
62441451115302555
7163434214152524
oct23040263136547
94566328617788
101310011997543
11465633691127
12191a8044aa5b
13966c2425742
144759515214b
1524122da2e98
hex13102ccbd67

1310011997543 has 2 divisors, whose sum is σ = 1310011997544. Its totient is φ = 1310011997542.

The previous prime is 1310011997519. The next prime is 1310011997621. The reversal of 1310011997543 is 3457991100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310011997543 - 236 = 1241292520807 is a prime.

It is a super-2 number, since 2×13100119975432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310011997494 and 1310011997503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310011997143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655005998771 + 655005998772.

It is an arithmetic number, because the mean of its divisors is an integer number (655005998772).

Almost surely, 21310011997543 is an apocalyptic number.

1310011997543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310011997543 is an equidigital number, since it uses as much as digits as its factorization.

1310011997543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 102060, while the sum is 44.

The spelling of 1310011997543 in words is "one trillion, three hundred ten billion, eleven million, nine hundred ninety-seven thousand, five hundred forty-three".