Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0000110101010100001111 |
3 | 1201101100200220101100111211 |
4 | 2332220130000311110033 |
5 | 3204113021234430411 |
6 | 43510040120355251 |
7 | 2521311122502163 |
oct | 276503400652417 |
9 | 51340626340454 |
10 | 13100120233231 |
11 | 41a08033968a9 |
12 | 1576a83915b27 |
13 | 74044a373c85 |
14 | 334099022ca3 |
15 | 17ab6e221221 |
hex | bea1c03550f |
13100120233231 has 2 divisors, whose sum is σ = 13100120233232. Its totient is φ = 13100120233230.
The previous prime is 13100120233169. The next prime is 13100120233271. The reversal of 13100120233231 is 13233202100131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13100120233231 - 211 = 13100120231183 is a prime.
It is a super-2 number, since 2×131001202332312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100120233271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550060116615 + 6550060116616.
It is an arithmetic number, because the mean of its divisors is an integer number (6550060116616).
Almost surely, 213100120233231 is an apocalyptic number.
13100120233231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100120233231 is an equidigital number, since it uses as much as digits as its factorization.
13100120233231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13100120233231 its reverse (13233202100131), we get a palindrome (26333322333362).
The spelling of 13100120233231 in words is "thirteen trillion, one hundred billion, one hundred twenty million, two hundred thirty-three thousand, two hundred thirty-one".
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