Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1111101110010110111 |
3 | 110112010200220002101222 |
4 | 1322000101331302313 |
5 | 4121242302241322 |
6 | 140103042340555 |
7 | 12315221634014 |
oct | 1720021756267 |
9 | 415120802358 |
10 | 131001212087 |
11 | 50614850639 |
12 | 2148005a75b |
13 | c479447615 |
14 | 64aa45070b |
15 | 361abd3e42 |
hex | 1e8047dcb7 |
131001212087 has 2 divisors, whose sum is σ = 131001212088. Its totient is φ = 131001212086.
The previous prime is 131001212039. The next prime is 131001212123. The reversal of 131001212087 is 780212100131.
It is a strong prime.
It is an emirp because it is prime and its reverse (780212100131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131001212087 - 212 = 131001207991 is a prime.
It is a super-2 number, since 2×1310012120872 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001212387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500606043 + 65500606044.
It is an arithmetic number, because the mean of its divisors is an integer number (65500606044).
Almost surely, 2131001212087 is an apocalyptic number.
131001212087 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001212087 is an equidigital number, since it uses as much as digits as its factorization.
131001212087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 26.
The spelling of 131001212087 in words is "one hundred thirty-one billion, one million, two hundred twelve thousand, eighty-seven".
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