131001243431 has 2 divisors, whose sum is σ = 131001243432. Its totient is φ = 131001243430.

The previous prime is 131001243427. The next prime is 131001243437. The reversal of 131001243431 is 134342100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131001243431 - 2² = 131001243427 is a prime.

It is a super-2 number, since 2×131001243431² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001243397 and 131001243406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001243437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500621715 + 65500621716.

It is an arithmetic number, because the mean of its divisors is an integer number (65500621716).

Almost surely, 2^131001243431 is an apocalyptic number.

131001243431 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001243431 is an equidigital number, since it uses as much as digits as its factorization.

131001243431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131001243431 its reverse (134342100131), we get a palindrome (265343343562).

The spelling of 131001243431 in words is "one hundred thirty-one billion, one million, two hundred forty-three thousand, four hundred thirty-one".