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1310013002110 = 25131001300211
BaseRepresentation
bin10011000100000010110…
…111000001000101111110
311122020101001120122220011
4103010002313001011332
5132430401312031420
62441451153013434
7163434225535351
oct23040267010576
94566331518804
101310013002110
1146563420794a
12191a8085427a
13966c26b7a67
1447595334298
152412300095a
hex13102dc117e

1310013002110 has 8 divisors (see below), whose sum is σ = 2358023403816. Its totient is φ = 524005200840.

The previous prime is 1310013002101. The next prime is 1310013002161. The reversal of 1310013002110 is 112003100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13100130021102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65500650096 + ... + 65500650115.

It is an arithmetic number, because the mean of its divisors is an integer number (294752925477).

Almost surely, 21310013002110 is an apocalyptic number.

1310013002110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310013002110 is a deficient number, since it is larger than the sum of its proper divisors (1048010401706).

1310013002110 is a wasteful number, since it uses less digits than its factorization.

1310013002110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131001300218.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1310013002110 its reverse (112003100131), we get a palindrome (1422016102241).

The spelling of 1310013002110 in words is "one trillion, three hundred ten billion, thirteen million, two thousand, one hundred ten".

Divisors: 1 2 5 10 131001300211 262002600422 655006501055 1310013002110