Base | Representation |
---|---|
bin | 111101000000001001… |
… | …0010110011111100101 |
3 | 110112010201002020011212 |
4 | 1322000102112133211 |
5 | 4121242314011003 |
6 | 140103044441205 |
7 | 12315222534656 |
oct | 1720022263745 |
9 | 415121066155 |
10 | 131001313253 |
11 | 5061490a648 |
12 | 214800a9205 |
13 | c479481695 |
14 | 64aa47952d |
15 | 361ac03dd8 |
hex | 1e804967e5 |
131001313253 has 2 divisors, whose sum is σ = 131001313254. Its totient is φ = 131001313252.
The previous prime is 131001313229. The next prime is 131001313271. The reversal of 131001313253 is 352313100131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110478458689 + 20522854564 = 332383^2 + 143258^2 .
It is a cyclic number.
It is not a de Polignac number, because 131001313253 - 26 = 131001313189 is a prime.
It is a super-2 number, since 2×1310013132532 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001313283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500656626 + 65500656627.
It is an arithmetic number, because the mean of its divisors is an integer number (65500656627).
Almost surely, 2131001313253 is an apocalyptic number.
It is an amenable number.
131001313253 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001313253 is an equidigital number, since it uses as much as digits as its factorization.
131001313253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 131001313253 its reverse (352313100131), we get a palindrome (483314413384).
The spelling of 131001313253 in words is "one hundred thirty-one billion, one million, three hundred thirteen thousand, two hundred fifty-three".
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