Base | Representation |
---|---|
bin | 10011000100000010110… |
… | …111110110110010001111 |
3 | 11122020101001222211120101 |
4 | 103010002313312302033 |
5 | 132430401341101111 |
6 | 2441451201431531 |
7 | 163434230442463 |
oct | 23040267666217 |
9 | 4566331884511 |
10 | 1310013222031 |
11 | 4656343480a8 |
12 | 191a8093b5a7 |
13 | 966c2763ba7 |
14 | 475953904a3 |
15 | 24123045bc1 |
hex | 13102df6c8f |
1310013222031 has 2 divisors, whose sum is σ = 1310013222032. Its totient is φ = 1310013222030.
The previous prime is 1310013221989. The next prime is 1310013222097. The reversal of 1310013222031 is 1302223100131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1302223100131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310013222031 - 29 = 1310013221519 is a prime.
It is a super-2 number, since 2×13100132220312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310013222131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006611015 + 655006611016.
It is an arithmetic number, because the mean of its divisors is an integer number (655006611016).
Almost surely, 21310013222031 is an apocalyptic number.
1310013222031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310013222031 is an equidigital number, since it uses as much as digits as its factorization.
1310013222031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1310013222031 its reverse (1302223100131), we get a palindrome (2612236322162).
The spelling of 1310013222031 in words is "one trillion, three hundred ten billion, thirteen million, two hundred twenty-two thousand, thirty-one".
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