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131001341330479 is a prime number
BaseRepresentation
bin11101110010010100100000…
…011010100100010000101111
3122011211121100201101100202111
4131302110200122210100233
5114132311221340033404
61142341104013504451
736410351234450134
oct3562244032442057
9564747321340674
10131001341330479
11388173a1a8a604
1212838b301a2127
1358134b16c9ca9
14244c6da80458b
1510229a3966104
hex7725206a442f

131001341330479 has 2 divisors, whose sum is σ = 131001341330480. Its totient is φ = 131001341330478.

The previous prime is 131001341330411. The next prime is 131001341330549. The reversal of 131001341330479 is 974033143100131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131001341330479 is a prime.

It is a super-2 number, since 2×1310013413304792 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001341330179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500670665239 + 65500670665240.

It is an arithmetic number, because the mean of its divisors is an integer number (65500670665240).

Almost surely, 2131001341330479 is an apocalyptic number.

131001341330479 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001341330479 is an equidigital number, since it uses as much as digits as its factorization.

131001341330479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 131001341330479 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, three hundred thirty thousand, four hundred seventy-nine".