Base | Representation |
---|---|
bin | 11101110010010100100000… |
… | …011010100100010000101111 |
3 | 122011211121100201101100202111 |
4 | 131302110200122210100233 |
5 | 114132311221340033404 |
6 | 1142341104013504451 |
7 | 36410351234450134 |
oct | 3562244032442057 |
9 | 564747321340674 |
10 | 131001341330479 |
11 | 388173a1a8a604 |
12 | 12838b301a2127 |
13 | 58134b16c9ca9 |
14 | 244c6da80458b |
15 | 10229a3966104 |
hex | 7725206a442f |
131001341330479 has 2 divisors, whose sum is σ = 131001341330480. Its totient is φ = 131001341330478.
The previous prime is 131001341330411. The next prime is 131001341330549. The reversal of 131001341330479 is 974033143100131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131001341330479 is a prime.
It is a super-2 number, since 2×1310013413304792 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001341330179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500670665239 + 65500670665240.
It is an arithmetic number, because the mean of its divisors is an integer number (65500670665240).
Almost surely, 2131001341330479 is an apocalyptic number.
131001341330479 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001341330479 is an equidigital number, since it uses as much as digits as its factorization.
131001341330479 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 40.
The spelling of 131001341330479 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, three hundred thirty thousand, four hundred seventy-nine".
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