Base | Representation |
---|---|
bin | 100111000010101… |
… | …0011100000010001 |
3 | 10101022000120121221 |
4 | 1032011103200101 |
5 | 10140330412312 |
6 | 333554045041 |
7 | 44314634134 |
oct | 11605234021 |
9 | 3338016557 |
10 | 1310013457 |
11 | 612517555 |
12 | 306879781 |
13 | 17b5329bc |
14 | c5daa21b |
15 | 7a01c207 |
hex | 4e153811 |
1310013457 has 2 divisors, whose sum is σ = 1310013458. Its totient is φ = 1310013456.
The previous prime is 1310013451. The next prime is 1310013479. The reversal of 1310013457 is 7543100131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1158993936 + 151019521 = 34044^2 + 12289^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310013457 - 215 = 1309980689 is a prime.
It is a super-2 number, since 2×13100134572 = 3432270515042181698, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310013451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006728 + 655006729.
It is an arithmetic number, because the mean of its divisors is an integer number (655006729).
Almost surely, 21310013457 is an apocalyptic number.
It is an amenable number.
1310013457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310013457 is an equidigital number, since it uses as much as digits as its factorization.
1310013457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
The square root of 1310013457 is about 36194.1080426083. The cubic root of 1310013457 is about 1094.1879280267.
Adding to 1310013457 its reverse (7543100131), we get a palindrome (8853113588).
The spelling of 1310013457 in words is "one billion, three hundred ten million, thirteen thousand, four hundred fifty-seven".
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