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131001353134 = 265500676567
BaseRepresentation
bin111101000000001001…
…0100000001110101110
3110112010201011020212221
41322000102200032232
54121242321300014
6140103045345554
712315223062151
oct1720022401656
9415121136787
10131001353134
1150614937603
12214801082ba
13c479496892
1464aa489c98
15361ac10b24
hex1e804a03ae

131001353134 has 4 divisors (see below), whose sum is σ = 196502029704. Its totient is φ = 65500676566.

The previous prime is 131001353123. The next prime is 131001353137. The reversal of 131001353134 is 431353100131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 431353100131 = 500538617927.

It is a super-2 number, since 2×1310013531342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001353099 and 131001353108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131001353137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750338282 + ... + 32750338285.

It is an arithmetic number, because the mean of its divisors is an integer number (49125507426).

Almost surely, 2131001353134 is an apocalyptic number.

131001353134 is a deficient number, since it is larger than the sum of its proper divisors (65500676570).

131001353134 is an equidigital number, since it uses as much as digits as its factorization.

131001353134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65500676569.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 131001353134 its reverse (431353100131), we get a palindrome (562354453265).

The spelling of 131001353134 in words is "one hundred thirty-one billion, one million, three hundred fifty-three thousand, one hundred thirty-four".

Divisors: 1 2 65500676567 131001353134