Base | Representation |
---|---|
bin | 1011111010100001110100… |
… | …1101000111100111001000 |
3 | 1201101100202022000100110002 |
4 | 2332220131031013213020 |
5 | 3204113041344343422 |
6 | 43510042113142132 |
7 | 2521311454462064 |
oct | 276503515074710 |
9 | 51340668010402 |
10 | 13100140231112 |
11 | 41a0813705580 |
12 | 1576a8a55a948 |
13 | 74045155643c |
14 | 33409b94aaa4 |
15 | 17ab70d71692 |
hex | bea1d3479c8 |
13100140231112 has 32 divisors (see below), whose sum is σ = 27365863547520. Its totient is φ = 5827915381440.
The previous prime is 13100140231093. The next prime is 13100140231133. The reversal of 13100140231112 is 21113204100131.
It is a super-4 number, since 4×131001402311124 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1583668523 + ... + 1583676794.
It is an arithmetic number, because the mean of its divisors is an integer number (855183235860).
Almost surely, 213100140231112 is an apocalyptic number.
It is an amenable number.
13100140231112 is an abundant number, since it is smaller than the sum of its proper divisors (14265723316408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100140231112 is a wasteful number, since it uses less digits than its factorization.
13100140231112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3167345381 (or 3167345377 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13100140231112 its reverse (21113204100131), we get a palindrome (34213344331243).
The spelling of 13100140231112 in words is "thirteen trillion, one hundred billion, one hundred forty million, two hundred thirty-one thousand, one hundred twelve".
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