Base | Representation |
---|---|
bin | 11101110010010101001010… |
… | …111101011011111100001000 |
3 | 122011211200012110111100100212 |
4 | 131302111022331123330020 |
5 | 114132314202102131004 |
6 | 1142341302512420252 |
7 | 36410405022511130 |
oct | 3562251275337410 |
9 | 564750173440325 |
10 | 131002055114504 |
11 | 38817728994062 |
12 | 128390ab247688 |
13 | 58135965543c2 |
14 | 244c767529ac0 |
15 | 10229e645c96e |
hex | 77254af5bf08 |
131002055114504 has 64 divisors (see below), whose sum is σ = 282592004812800. Its totient is φ = 55769112360000.
The previous prime is 131002055114479. The next prime is 131002055114519. The reversal of 131002055114504 is 405411550200131.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171775229 + ... + 172536179.
It is an arithmetic number, because the mean of its divisors is an integer number (4415500075200).
Almost surely, 2131002055114504 is an apocalyptic number.
131002055114504 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
131002055114504 is an abundant number, since it is smaller than the sum of its proper divisors (151589949698296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131002055114504 is a wasteful number, since it uses less digits than its factorization.
131002055114504 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 781474 (or 781470 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 131002055114504 in words is "one hundred thirty-one trillion, two billion, fifty-five million, one hundred fourteen thousand, five hundred four".
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