1310021130000 has 400 divisors, whose sum is σ = 4711583010816. Its totient is φ = 310820160000.

The previous prime is 1310021129951. The next prime is 1310021130023. The reversal of 1310021130000 is 311200131.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×1310021130000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 15467769 + ... + 15552231.

Almost surely, 2^{1310021130000} is an apocalyptic number.

1310021130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1310021130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2355791505408).

1310021130000 is an abundant number, since it is smaller than the sum of its proper divisors (3401561880816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310021130000 is a wasteful number, since it uses less digits than its factorization.

1310021130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84552 (or 84531 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 1310021130000 its reverse (311200131), we get a palindrome (1310332330131).

The spelling of 1310021130000 in words is "one trillion, three hundred ten billion, twenty-one million, one hundred thirty thousand".