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131002122635633 is a prime number
BaseRepresentation
bin11101110010010101001110…
…111111000000100101110001
3122011211200101011112202221102
4131302111032333000211301
5114132314321343320013
61142341313323534145
736410406502441544
oct3562251677004561
9564750334482842
10131002122635633
1138817763011747
121283910998a355
1358135a7535832
14244c7724a485b
1510229ec348d58
hex77254efc0971

131002122635633 has 2 divisors, whose sum is σ = 131002122635634. Its totient is φ = 131002122635632.

The previous prime is 131002122635561. The next prime is 131002122635651. The reversal of 131002122635633 is 336536221200131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129045237796864 + 1956884838769 = 11359808^2 + 1398887^2 .

It is a cyclic number.

It is not a de Polignac number, because 131002122635633 - 216 = 131002122570097 is a prime.

It is a super-2 number, since 2×1310021226356332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131002122635233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501061317816 + 65501061317817.

It is an arithmetic number, because the mean of its divisors is an integer number (65501061317817).

Almost surely, 2131002122635633 is an apocalyptic number.

It is an amenable number.

131002122635633 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002122635633 is an equidigital number, since it uses as much as digits as its factorization.

131002122635633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 38.

Adding to 131002122635633 its reverse (336536221200131), we get a palindrome (467538343835764).

The spelling of 131002122635633 in words is "one hundred thirty-one trillion, two billion, one hundred twenty-two million, six hundred thirty-five thousand, six hundred thirty-three".