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131002131024157 is a prime number
BaseRepresentation
bin11101110010010101001111…
…011111000000100100011101
3122011211200101202022221211111
4131302111033133000210131
5114132314331020233112
61142341314223422021
736410406633650101
oct3562251737004435
9564750352287744
10131002131024157
1138817767821108
1212839110754911
1358135a91b1a63
14244c773649901
1510229ece545a7
hex77254f7c091d

131002131024157 has 2 divisors, whose sum is σ = 131002131024158. Its totient is φ = 131002131024156.

The previous prime is 131002131024143. The next prime is 131002131024217. The reversal of 131002131024157 is 751420131200131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130060476212836 + 941654811321 = 11404406^2 + 970389^2 .

It is a cyclic number.

It is not a de Polignac number, because 131002131024157 - 235 = 130967771285789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131002131028157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065512078 + 65501065512079.

It is an arithmetic number, because the mean of its divisors is an integer number (65501065512079).

Almost surely, 2131002131024157 is an apocalyptic number.

It is an amenable number.

131002131024157 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002131024157 is an equidigital number, since it uses as much as digits as its factorization.

131002131024157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 131002131024157 its reverse (751420131200131), we get a palindrome (882422262224288).

The spelling of 131002131024157 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, one hundred fifty-seven".