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131002131024517 is a prime number
BaseRepresentation
bin11101110010010101001111…
…011111000000101010000101
3122011211200101202022222022211
4131302111033133000222011
5114132314331020241032
61142341314223423421
736410406633651124
oct3562251737005205
9564750352288284
10131002131024517
1138817767821405
1212839110754b71
1358135a91b1c7c
14244c773649abb
1510229ece54747
hex77254f7c0a85

131002131024517 has 2 divisors, whose sum is σ = 131002131024518. Its totient is φ = 131002131024516.

The previous prime is 131002131024497. The next prime is 131002131024601. The reversal of 131002131024517 is 715420131200131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88762608374881 + 42239522649636 = 9421391^2 + 6499194^2 .

It is a cyclic number.

It is not a de Polignac number, because 131002131024517 - 227 = 131001996806789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131002131024217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065512258 + 65501065512259.

It is an arithmetic number, because the mean of its divisors is an integer number (65501065512259).

Almost surely, 2131002131024517 is an apocalyptic number.

It is an amenable number.

131002131024517 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002131024517 is an equidigital number, since it uses as much as digits as its factorization.

131002131024517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 131002131024517 its reverse (715420131200131), we get a palindrome (846422262224648).

The spelling of 131002131024517 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, five hundred seventeen".