13100244131041 has 2 divisors, whose sum is σ = 13100244131042. Its totient is φ = 13100244131040.

The previous prime is 13100244131033. The next prime is 13100244131063. The reversal of 13100244131041 is 14013144200131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9198355028641 + 3901889102400 = 3032879^2 + 1975320^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100244131041 - 2³ = 13100244131033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13100244130997 and 13100244131015.

It is not a weakly prime, because it can be changed into another prime (13100244131341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550122065520 + 6550122065521.

It is an arithmetic number, because the mean of its divisors is an integer number (6550122065521).

Almost surely, 2^{13100244131041} is an apocalyptic number.

It is an amenable number.

13100244131041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100244131041 is an equidigital number, since it uses as much as digits as its factorization.

13100244131041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13100244131041 its reverse (14013144200131), we get a palindrome (27113388331172).

The spelling of 13100244131041 in words is "thirteen trillion, one hundred billion, two hundred forty-four million, one hundred thirty-one thousand, forty-one".