Base | Representation |
---|---|
bin | 11101110010010101100010… |
… | …000001101011100111010011 |
3 | 122011211201012102200102010102 |
4 | 131302111202001223213103 |
5 | 114132321000134301001 |
6 | 1142341405135123015 |
7 | 36410420432042165 |
oct | 3562254201534723 |
9 | 564751172612112 |
10 | 131002442103251 |
11 | 38817907382474 |
12 | 1283919897346b |
13 | 581362878b624 |
14 | 244c7a2aa4935 |
15 | 1022a1a400e6b |
hex | 77256206b9d3 |
131002442103251 has 2 divisors, whose sum is σ = 131002442103252. Its totient is φ = 131002442103250.
The previous prime is 131002442103163. The next prime is 131002442103277. The reversal of 131002442103251 is 152301244200131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131002442103251 is a prime.
It is not a weakly prime, because it can be changed into another prime (131002442106251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501221051625 + 65501221051626.
It is an arithmetic number, because the mean of its divisors is an integer number (65501221051626).
Almost surely, 2131002442103251 is an apocalyptic number.
131002442103251 is a deficient number, since it is larger than the sum of its proper divisors (1).
131002442103251 is an equidigital number, since it uses as much as digits as its factorization.
131002442103251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 131002442103251 its reverse (152301244200131), we get a palindrome (283303686303382).
The spelling of 131002442103251 in words is "one hundred thirty-one trillion, two billion, four hundred forty-two million, one hundred three thousand, two hundred fifty-one".
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