Base | Representation |
---|---|
bin | 111101000000001100… |
… | …0110101000010000111 |
3 | 110112010211021111100001 |
4 | 1322000120311002013 |
5 | 4121243232324312 |
6 | 140103145102131 |
7 | 12315243136165 |
oct | 1720030650207 |
9 | 415124244301 |
10 | 131003011207 |
11 | 5061586a312 |
12 | 21480787947 |
13 | c4799274a3 |
14 | 64aa79c235 |
15 | 361ae3c057 |
hex | 1e80635087 |
131003011207 has 2 divisors, whose sum is σ = 131003011208. Its totient is φ = 131003011206.
The previous prime is 131003011193. The next prime is 131003011333. The reversal of 131003011207 is 702110300131.
It is a weak prime.
It is an emirp because it is prime and its reverse (702110300131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131003011207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131003017207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501505603 + 65501505604.
It is an arithmetic number, because the mean of its divisors is an integer number (65501505604).
Almost surely, 2131003011207 is an apocalyptic number.
131003011207 is a deficient number, since it is larger than the sum of its proper divisors (1).
131003011207 is an equidigital number, since it uses as much as digits as its factorization.
131003011207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 131003011207 its reverse (702110300131), we get a palindrome (833113311338).
The spelling of 131003011207 in words is "one hundred thirty-one billion, three million, eleven thousand, two hundred seven".
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