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13100323113247 is a prime number
BaseRepresentation
bin1011111010100010100000…
…0110110000100100011111
31201101101020001010201120111
42332220220012300210133
53204113430204110442
643510112205030451
72521316135113126
oct276505006604437
951341201121514
1013100323113247
1141a08a7966637
121576b1b855427
137404803c9116
143340b7d54abd
1517ab81e48b17
hexbea281b091f

13100323113247 has 2 divisors, whose sum is σ = 13100323113248. Its totient is φ = 13100323113246.

The previous prime is 13100323113233. The next prime is 13100323113277. The reversal of 13100323113247 is 74231132300131.

It is a weak prime.

It is an emirp because it is prime and its reverse (74231132300131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100323113247 - 211 = 13100323111199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100323113217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550161556623 + 6550161556624.

It is an arithmetic number, because the mean of its divisors is an integer number (6550161556624).

Almost surely, 213100323113247 is an apocalyptic number.

13100323113247 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100323113247 is an equidigital number, since it uses as much as digits as its factorization.

13100323113247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 13100323113247 its reverse (74231132300131), we get a palindrome (87331455413378).

The spelling of 13100323113247 in words is "thirteen trillion, one hundred billion, three hundred twenty-three million, one hundred thirteen thousand, two hundred forty-seven".