13100330119 has 2 divisors, whose sum is σ = 13100330120. Its totient is φ = 13100330118.

The previous prime is 13100330093. The next prime is 13100330137. The reversal of 13100330119 is 91103300131.

13100330119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (91103300131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100330119 - 2¹⁵ = 13100297351 is a prime.

It is a super-2 number, since 2×13100330119² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13100330119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100331119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550165059 + 6550165060.

It is an arithmetic number, because the mean of its divisors is an integer number (6550165060).

Almost surely, 2^13100330119 is an apocalyptic number.

13100330119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100330119 is an equidigital number, since it uses as much as digits as its factorization.

13100330119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 22.

The spelling of 13100330119 in words is "thirteen billion, one hundred million, three hundred thirty thousand, one hundred nineteen".