Base | Representation |
---|---|
bin | 111101000000001100… |
… | …1111100101000000011 |
3 | 110112010211211101120221 |
4 | 1322000121330220003 |
5 | 4121243321220301 |
6 | 140103155243511 |
7 | 12315245500135 |
oct | 1720031745003 |
9 | 415124741527 |
10 | 131003304451 |
11 | 50615a4a668 |
12 | 214808a9597 |
13 | c4799caac6 |
14 | 64aa837055 |
15 | 361ae98da1 |
hex | 1e8067ca03 |
131003304451 has 2 divisors, whose sum is σ = 131003304452. Its totient is φ = 131003304450.
The previous prime is 131003304379. The next prime is 131003304463. The reversal of 131003304451 is 154403300131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131003304451 - 29 = 131003303939 is a prime.
It is a super-2 number, since 2×1310033044512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131003304151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501652225 + 65501652226.
It is an arithmetic number, because the mean of its divisors is an integer number (65501652226).
Almost surely, 2131003304451 is an apocalyptic number.
131003304451 is a deficient number, since it is larger than the sum of its proper divisors (1).
131003304451 is an equidigital number, since it uses as much as digits as its factorization.
131003304451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 131003304451 its reverse (154403300131), we get a palindrome (285406604582).
The spelling of 131003304451 in words is "one hundred thirty-one billion, three million, three hundred four thousand, four hundred fifty-one".
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