Base | Representation |
---|---|
bin | 1011111010100010100101… |
… | …0111111101100010000000 |
3 | 1201101101021112012012111202 |
4 | 2332220221113331202000 |
5 | 3204114001131300000 |
6 | 43510114245200332 |
7 | 2521316514051464 |
oct | 276505127754200 |
9 | 51341245165452 |
10 | 13100344400000 |
11 | 41a09089856a0 |
12 | 1576b26a000a8 |
13 | 740484940130 |
14 | 3340baad64a4 |
15 | 17ab83c50dd5 |
hex | bea295fd880 |
13100344400000 has 384 divisors, whose sum is σ = 38323951485120. Its totient is φ = 4397299200000.
The previous prime is 13100344399993. The next prime is 13100344400123. The reversal of 13100344400000 is 444300131.
It is a happy number.
13100344400000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131003444000002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 57085487 + ... + 57314513.
Almost surely, 213100344400000 is an apocalyptic number.
13100344400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100344400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19161975742560).
13100344400000 is an abundant number, since it is smaller than the sum of its proper divisors (25223607085120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100344400000 is an equidigital number, since it uses as much as digits as its factorization.
13100344400000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229090 (or 229058 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 13100344400000 its reverse (444300131), we get a palindrome (13100788700131).
The spelling of 13100344400000 in words is "thirteen trillion, one hundred billion, three hundred forty-four million, four hundred thousand".
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