1310040112 has 10 divisors (see below), whose sum is σ = 2538202748. Its totient is φ = 655020048.

The previous prime is 1310040103. The next prime is 1310040143. The reversal of 1310040112 is 2110400131.

It is a junction number, because it is equal to n+sod(n) for n = 1310040092 and 1310040101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40938738 + ... + 40938769.

Almost surely, 2^1310040112 is an apocalyptic number.

It is an amenable number.

1310040112 is a deficient number, since it is larger than the sum of its proper divisors (1228162636).

1310040112 is an equidigital number, since it uses as much as digits as its factorization.

1310040112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81877515 (or 81877509 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1310040112 is about 36194.4762636511. The cubic root of 1310040112 is about 1094.1953491671.

Adding to 1310040112 its reverse (2110400131), we get a palindrome (3420440243).

The spelling of 1310040112 in words is "one billion, three hundred ten million, forty thousand, one hundred twelve".