Base | Representation |
---|---|
bin | 10011000100000100101… |
… | …010101001100100101001 |
3 | 11122020110011121200122021 |
4 | 103010010222221210221 |
5 | 132430432042030343 |
6 | 2441454154424441 |
7 | 163435044304525 |
oct | 23040452514451 |
9 | 4566404550567 |
10 | 1310043314473 |
11 | 46564a330a93 |
12 | 191a8aa32121 |
13 | 966c8a6bc7a |
14 | 47599384d85 |
15 | 241259dc0ed |
hex | 13104aa9929 |
1310043314473 has 2 divisors, whose sum is σ = 1310043314474. Its totient is φ = 1310043314472.
The previous prime is 1310043314417. The next prime is 1310043314477. The reversal of 1310043314473 is 3744133400131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1077668219664 + 232375094809 = 1038108^2 + 482053^2 .
It is an emirp because it is prime and its reverse (3744133400131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310043314473 - 217 = 1310043183401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310043314477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655021657236 + 655021657237.
It is an arithmetic number, because the mean of its divisors is an integer number (655021657237).
Almost surely, 21310043314473 is an apocalyptic number.
It is an amenable number.
1310043314473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310043314473 is an equidigital number, since it uses as much as digits as its factorization.
1310043314473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
The spelling of 1310043314473 in words is "one trillion, three hundred ten billion, forty-three million, three hundred fourteen thousand, four hundred seventy-three".
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