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131004400157 is a prime number
BaseRepresentation
bin111101000000001111…
…0001000001000011101
3110112010220220001121122
41322000132020020131
54121244111301112
6140103234540325
712315261012461
oct1720036101035
9415126801548
10131004400157
1150616628904
12214811376a5
13c479cc2757
1464aaa404a1
15361b113872
hex1e8078821d

131004400157 has 2 divisors, whose sum is σ = 131004400158. Its totient is φ = 131004400156.

The previous prime is 131004400129. The next prime is 131004400229. The reversal of 131004400157 is 751004400131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130978124281 + 26275876 = 361909^2 + 5126^2 .

It is a cyclic number.

It is not a de Polignac number, because 131004400157 - 28 = 131004399901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131004490157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502200078 + 65502200079.

It is an arithmetic number, because the mean of its divisors is an integer number (65502200079).

Almost surely, 2131004400157 is an apocalyptic number.

It is an amenable number.

131004400157 is a deficient number, since it is larger than the sum of its proper divisors (1).

131004400157 is an equidigital number, since it uses as much as digits as its factorization.

131004400157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 26.

Subtracting from 131004400157 its sum of digits (26), we obtain a palindrome (131004400131).

Adding to 131004400157 its reverse (751004400131), we get a palindrome (882008800288).

The spelling of 131004400157 in words is "one hundred thirty-one billion, four million, four hundred thousand, one hundred fifty-seven".