Base | Representation |
---|---|
bin | 11000011001101100… |
… | …01110010110010110 |
3 | 1020210222210110101201 |
4 | 30030312032112112 |
5 | 203312203134110 |
6 | 10003535543114 |
7 | 642432633313 |
oct | 141466162626 |
9 | 36728713351 |
10 | 13100443030 |
11 | 5612949824 |
12 | 265738aa9a |
13 | 130a13c04c |
14 | 8c3c33d0a |
15 | 51a192b3a |
hex | 30cd8e596 |
13100443030 has 8 divisors (see below), whose sum is σ = 23580797472. Its totient is φ = 5240177208.
The previous prime is 13100442983. The next prime is 13100443087. The reversal of 13100443030 is 3034400131.
13100443030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13100442989 and 13100443007.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655022142 + ... + 655022161.
It is an arithmetic number, because the mean of its divisors is an integer number (2947599684).
Almost surely, 213100443030 is an apocalyptic number.
13100443030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13100443030 is a deficient number, since it is larger than the sum of its proper divisors (10480354442).
13100443030 is a wasteful number, since it uses less digits than its factorization.
13100443030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1310044310.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13100443030 its reverse (3034400131), we get a palindrome (16134843161).
The spelling of 13100443030 in words is "thirteen billion, one hundred million, four hundred forty-three thousand, thirty".
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