Base | Representation |
---|---|
bin | 111101000000010000… |
… | …1010000110011111110 |
3 | 110112010222102211011112 |
4 | 1322000201100303332 |
5 | 4121244314102032 |
6 | 140103304322022 |
7 | 12315301005104 |
oct | 1720041206376 |
9 | 415128384145 |
10 | 131005222142 |
11 | 5061703a433 |
12 | 21481473312 |
13 | c47a21c932 |
14 | 64aabb5c74 |
15 | 361b2271b2 |
hex | 1e80850cfe |
131005222142 has 4 divisors (see below), whose sum is σ = 196507833216. Its totient is φ = 65502611070.
The previous prime is 131005222133. The next prime is 131005222147. The reversal of 131005222142 is 241222500131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241222500131 = 53 ⋅4551367927.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131005222147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32751305534 + ... + 32751305537.
It is an arithmetic number, because the mean of its divisors is an integer number (49126958304).
Almost surely, 2131005222142 is an apocalyptic number.
131005222142 is a deficient number, since it is larger than the sum of its proper divisors (65502611074).
131005222142 is an equidigital number, since it uses as much as digits as its factorization.
131005222142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65502611073.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 131005222142 its reverse (241222500131), we get a palindrome (372227722273).
The spelling of 131005222142 in words is "one hundred thirty-one billion, five million, two hundred twenty-two thousand, one hundred forty-two".
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