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13100605081 is a prime number
BaseRepresentation
bin11000011001101101…
…10101111010011001
31020211000002200200121
430030312311322121
5203312223330311
610003543233241
7642434206624
oct141466657231
936730080617
1013100605081
115612a4a553
122657448821
13130a197a35
148c3c76dbb
1551a1c5b71
hex30cdb5e99

13100605081 has 2 divisors, whose sum is σ = 13100605082. Its totient is φ = 13100605080.

The previous prime is 13100605009. The next prime is 13100605097. The reversal of 13100605081 is 18050600131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12795229456 + 305375625 = 113116^2 + 17475^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100605081 - 213 = 13100596889 is a prime.

It is a super-2 number, since 2×131006050812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100605481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550302540 + 6550302541.

It is an arithmetic number, because the mean of its divisors is an integer number (6550302541).

Almost surely, 213100605081 is an apocalyptic number.

It is an amenable number.

13100605081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100605081 is an equidigital number, since it uses as much as digits as its factorization.

13100605081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

The spelling of 13100605081 in words is "thirteen billion, one hundred million, six hundred five thousand, eighty-one".