13100643411311 has 2 divisors, whose sum is σ = 13100643411312. Its totient is φ = 13100643411310.

The previous prime is 13100643411287. The next prime is 13100643411329. The reversal of 13100643411311 is 11311434600131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100643411311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100643411371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550321705655 + 6550321705656.

It is an arithmetic number, because the mean of its divisors is an integer number (6550321705656).

Almost surely, 2^{13100643411311} is an apocalyptic number.

13100643411311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100643411311 is an equidigital number, since it uses as much as digits as its factorization.

13100643411311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 13100643411311 in words is "thirteen trillion, one hundred billion, six hundred forty-three million, four hundred eleven thousand, three hundred eleven".