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13101011041 is a prime number
BaseRepresentation
bin11000011001110000…
…11001000001100001
31020211000212022120011
430030320121001201
5203312324323131
610004000044521
7642440520316
oct141470310141
936730768504
1013101011041
1156131a7558
122657603741
13130a2aa751
148c3d40d0d
1551a2560b1
hex30ce19061

13101011041 has 2 divisors, whose sum is σ = 13101011042. Its totient is φ = 13101011040.

The previous prime is 13101011017. The next prime is 13101011047. The reversal of 13101011041 is 14011010131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9851555025 + 3249456016 = 99255^2 + 57004^2 .

It is an emirp because it is prime and its reverse (14011010131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101011041 - 211 = 13101008993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101011047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550505520 + 6550505521.

It is an arithmetic number, because the mean of its divisors is an integer number (6550505521).

Almost surely, 213101011041 is an apocalyptic number.

It is an amenable number.

13101011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101011041 is an equidigital number, since it uses as much as digits as its factorization.

13101011041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 13101011041 its reverse (14011010131), we get a palindrome (27112021172).

The spelling of 13101011041 in words is "thirteen billion, one hundred one million, eleven thousand, forty-one".